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6x^2-30x-36=11
We move all terms to the left:
6x^2-30x-36-(11)=0
We add all the numbers together, and all the variables
6x^2-30x-47=0
a = 6; b = -30; c = -47;
Δ = b2-4ac
Δ = -302-4·6·(-47)
Δ = 2028
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2028}=\sqrt{676*3}=\sqrt{676}*\sqrt{3}=26\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-26\sqrt{3}}{2*6}=\frac{30-26\sqrt{3}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+26\sqrt{3}}{2*6}=\frac{30+26\sqrt{3}}{12} $
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